A subnormal subgroup weakens normality by allowing a finite sequence of normal extensions up to the ambient group. The relation retains enough transitivity and closure to describe nilpotent groups, Fitting subgroups, components, and minimal normal subgroups. …
作者 Math.SX
A subnormal subgroup weakens normality by allowing a finite sequence of normal extensions up to the ambient group. The relation retains enough transitivity and closure to describe nilpotent groups, Fitting subgroups, components, and minimal normal subgroups. Wielandt's theorem that the join of two subnormal subgroups of a finite group is again subnormal is the central closure result. [@isaacs2008]
Definition
The notation \(H\triangleleft\triangleleft G\) is common. Each \(H_i\) need only be normal in the next member \(H_{i+1}\), not in all of \(G\).
Elementary properties
Subnormality is transitive: chains for \(H\triangleleft\triangleleft K\) and \(K\triangleleft\triangleleft G\) concatenate. It is also preserved by homomorphic images and inverse images.
Wielandt's join theorem
This is the most important and least obvious closure property. The product of normal subgroups is visibly normal, but two subnormal subgroups need not normalize one another, so their series cannot simply be spliced.
Characterization of finite nilpotent groups
Subnormal pi-subgroups and local cores
This is the encyclopedia-level conclusion extracted from Isaacs, Problem 2A.1: a seemingly weak subnormality condition becomes containment in the largest global normal local subgroup.
Relation with the Fitting subgroup
Normal closures and minimal normal subgroups
If \(S\triangleleft\triangleleft G\) is nonabelian simple, distinct conjugates of \(S\) are either equal or commute elementwise. Its normal closure
\[
S^G=\langle S^g\mid g\in G\rangle
\]
is therefore a direct product of mutually commuting simple conjugates and is a minimal normal subgroup of \(G\). This exercise-derived result is the prototype for the later theory of components and the layer.
Permutable subgroups and the zipper lemma
Suppose \(S\) permutes with each conjugate:
\[
SS^x=S^xS\qquad(x\in G).
\]
Then \(S\) is subnormal in a finite group. A direct series is not visible from the set products. The proof uses Wielandt's zipper lemma: if \(S\) is subnormal in every proper overgroup containing it but is not subnormal in \(G\), then \(S\) has a unique maximal overgroup. Conjugate-permutability forces a contradiction to that uniqueness.
This article integrates the intersection theorem, Wielandt's join theorem, the Fitting criterion, and the structural conclusions of Problems 2A.1 and 2A.7--2A.8 from Isaacs. Historical attribution and terminology were cross-checked against Wielandt's paper and the cited public encyclopedia revision. [@isaacs2008][@wielandt1939][@wikipedia-subnormal]